This section of the book is from the "Household Companion: The Practical Mechanic" book.
Area of a triangle | base * 1/2 altitude. |
Area of a parallelogram | multiply base by altitude. |
Area of a trapezoid | altitude * 1/2 the sum of parallel sides. |
Area of a trapezium | divide into two triangles and find area of the triangles. |
Circumference of circle | diameter * 3.1416. |
Diameter of circle | cicumference * .3183. |
Area of circle | square of the diameter multiplied by .7854. |
Area of circular ring | diameters of the two circles * difference of diameter and that product by .7854. |
Side of square that shall equal area of circle | diameter * . 8812 or circumference * .2821. |
Diameter of circle that shall contain area of a given square | side of square * 1.1284. |
Surface of cylinder or prism | area of both ends + length * circumference. |
Contents of cylinder or prism | area of end X length. |
Surface of sphere | diameter * circumference. |
Contents of sphere | diameter3 * .5236. |
Contents of pyramid or cone | area of base * 1/3 altitude. |
Surface of frustum of cone or pyramid | sum of circumference at both ends * slant height + area of both ends. |
Contents of frustrum of cone= or pyramid | multiply areas of two ends together and extract square root. Add to this root the two areas and * 1/3 altitude. |
Contents of a wedge | area of base * 1/2 altitude. |
 
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