This section is from the book "The English And American Mechanic", by B. Frank Van Cleve. Also available from Amazon: The English And American Mechanic.
Multiply the value of the material by 3 times the length in feet, and the breadth and square of the depth in inch and divide the product by twice the product of the distances of the weight, or stress from either end.
What is the weight a cast-iron bar, fixed at both ends, 2 ins. square and 5 feet in length, will bear without permanent injury, 2 feet from one end ?
225X3X5X2X22 27000
------------------=------=2250 lbs.
2x2X3 12
 
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